Important alert: (current site time 5/22/2013 6:38:21 PM EDT)
 

VB icon

Begginer Bin->Dec && Dec->Bin Convertor

Email
Submitted on: 9/14/2012 11:05:06 AM
By: Victor Chavauty  
Level: Beginner
User Rating: Unrated
Compatibility: C
Views: 1264
(About the author)
 
     trying to improve algorithms development.
 
code:
Can't Copy and Paste this?
Click here for a copy-and-paste friendly version of this code!
 
Terms of Agreement:   
By using this code, you agree to the following terms...   
  1. You may use this code in your own programs (and may compile it into a program and distribute it in compiled format for languages that allow it) freely and with no charge.
  2. You MAY NOT redistribute this code (for example to a web site) without written permission from the original author. Failure to do so is a violation of copyright laws.   
  3. You may link to this code from another website, but ONLY if it is not wrapped in a frame. 
  4. You will abide by any additional copyright restrictions which the author may have placed in the code or code's description.
				
//**************************************
// Name: Begginer Bin->Dec && Dec->Bin Convertor
// Description:trying to improve algorithms development.
// By: Victor Chavauty
//
//This code is copyrighted and has// limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=13848&lngWId=3//for details.//**************************************

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#define INITIAL_VALUE 0
void binary_to_decimal(int bin, int size);
void decimal_to_binary(int dec);
int main()
{
int binary;
int decimal;
int size_of_binary_number;
char get;
while(get != 'e' || get != 'E')
{
printf("-------------------------------------------------------\n");
printf("-------------------------------------------------------\n");
printf("-------------------------SELECT -----------------------\n");
printf("---------------------A FOR BIN->DEC -------------------\n");
printf("---------------------D FOR DEC->BIN -------------------\n");
printf("---------------------E TO EXIT -------------------\n");
printf("-------------------------------------------------------\n");
printf("-------------------------------------------------------\n");
printf("\n\n>>");
get = getch();
if(get == 'A' || get == 'a')
{
printf("\n\nPlease Write your Binary Number Here\n:");
scanf("%d", &binary);
size_of_binary_number = ceil(log10(binary));
system("cls");
binary_to_decimal(binary, size_of_binary_number);
}
else if(get == 'D' || get == 'd')
{
printf("\n\nPlease Write your Decimal Number Here\n:");
scanf("%d", &decimal);
system("cls");
decimal_to_binary(decimal);
}
else if(get == 'E' || get == 'e')
{
exit(0);
}
else
{
system("cls");
}
}
return 0;
}
void binary_to_decimal(int bin, int size)
{
int valor_binario = bin;
int valor_decimal[size];
int c, enumerado = INITIAL_VALUE;
int elev;
int decimal = INITIAL_VALUE;
for(c = 0;c <= size ;c++)
{
valor_decimal[enumerado] = valor_binario % 10;
valor_binario = valor_binario / 10;
enumerado++;
}
enumerado = INITIAL_VALUE;
for(c = 0; c <= size;c++)
{
if(valor_decimal[enumerado] == 1)
{
elev = pow(2, c);
decimal = decimal + elev;
}
enumerado++;
}
printf("Decimal Value: >> %d\n\n\n\n", decimal);
}
void decimal_to_binary(int dec)
{
int numero = dec; /* \ */
int check;
int valor = INITIAL_VALUE;
int a, c = INITIAL_VALUE;
int ab;
int valor_binario[320];
do
{
valor = pow(2, c);
c++;
}while(valor <= numero);
c = c - 2;
for(a = c;a >= 0; a--)
{
check = pow(2, a);
if(check <= numero)
{
numero = numero - check;
valor_binario[a - 1] = 1;
}
else
{
valor_binario[a - 1] = 0;
}
}
printf("Decimal Value: >> ");
for(ab = c; ab >= 0;ab--)
{
printf("%d", valor_binario[ab - 1]);
}
printf("\n\n\n\n");
}


Other 1 submission(s) by this author

 


Report Bad Submission
Use this form to tell us if this entry should be deleted (i.e contains no code, is a virus, etc.).
This submission should be removed because:

Your Vote

What do you think of this code (in the Beginner category)?
(The code with your highest vote will win this month's coding contest!)
Excellent  Good  Average  Below Average  Poor (See voting log ...)
 

Other User Comments

 There are no comments on this submission.
 

Add Your Feedback
Your feedback will be posted below and an email sent to the author. Please remember that the author was kind enough to share this with you, so any criticisms must be stated politely, or they will be deleted. (For feedback not related to this particular code, please click here instead.)
 

To post feedback, first please login.